Question

Solve for y, z, x or t:

Answer 1

Answer:

Step-by-step explanation:

$if~it ~is ~y+\frac{y}{a} =b\\then~\frac{ay+y}{a} =b\\ay+y=ab\\ y(a+1)=ab\\ y=\frac{ab}{a+1}$

$z-a=\frac{z}{b} \\z-\frac{z}{b} =a\\ \frac{bz-z}{b} =a\\bz-z=ab\\z(b-1)=ab\\z=\frac{ab}{b-1}$