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guajiro [1.7K]
4 years ago
9

Will mark brainliest and 15 points, please and thank you

Mathematics
1 answer:
mash [69]4 years ago
7 0

Answer:

Student 3 and Student 4

Step-by-step explanation:

Expand equation of Student 3

y = 2 (x - 1)

y = 2x -2, which is the same equation as student 4.

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Which is the equation of a line that is perpendicular to 8x + 6y = –5?
IrinaVladis [17]

The perpendicular line will have an equation of y=3/4x-3/4

To find this, we first have to solve our equation for slope intercept form.

8x + 6y = -5 ----> subtract 8x

6y = -8x + -5 ----> divide by 6

y = -4/3x - 5/6.

So we know the slope of this equation to be -4/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of 3/4. Since B is the only option with that slope, we know it to be the correct answer.

4 0
3 years ago
The perimeter of a square is the product of four and the length of a side. Which of the following function rules could be used t
Sindrei [870]
Perimeter of square is P = 4s.....s = length of 1 side

so ur function rule is : y = 4x
6 0
3 years ago
Someone help pls:( !!!!!!!!!!
lesantik [10]

Answer:

Multiply both sides by -2 and reverse the inequality symbol

Step-by-step explanation:

since it is division you want to make it multiplication so that you can get the answer easier

-1/2w<12

it cancels out the -1/2 than just multiply 12 and -2 you get -24

w > -24

8 0
3 years ago
Jessica is a custodian at Oracle Arena. She waxes 20 m² of the floor in = of an hour. Jessica
Wewaii [24]

The complete question is as follows:

Jessica is a custodian at Oracle Arena. She waxes 20 \mathbf{m^{2}} of the floor in \mathbf{\frac{3}{5}} of and hour. At this rate, how many square meters can she wax per hour ?

Answer:

\mathbf{\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}

Step-by-step explanation:

\textrm{rate}=\frac{\textrm{Area waxed in square meter}}{\textrm{Time taken to wax in hours}}

\textrm{rate}=\frac{20 \ \textrm{m}^{2}}{\frac{3}{5} \ \textrm{hours}}

\textrm{rate}=\frac{20\times5}{3}

\mathbf{rate=\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}

8 0
4 years ago
Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP
mixer [17]
Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
Slope for the second pair is -2/0

Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

6 0
3 years ago
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