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4 years ago

30 POINTS!

Mathematics

1 answer:

Luba_88 [7]4 years ago

6 0

Answer: 5.5 seconds

Since the penny is dropped and not thrown, the initial velocity is 0 and the initial height is given as 150m. Plugging these into the given equation result in $-4.9t^2+0t+150=-4.9t^2+150$ . To find how long it will take for the penny to hit the ground we set the equation equal to zero and solve for t. Since this doesn't factor, you'll need to use the quadratic formula:

$+/-\frac{\sqrt{0^2-4(-49)(150)}}{2(-49)} =+/-\frac{10\sqrt{15} }{7}=+/-5.533$ . Since time cannot be negative, the answer will be the positive 5.5 seconds.

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Analyze the end behavior of each function below. Then, choose one of the functions, and explain how you determined

kumpel [21]

Answer:

End behavior of a polynomial function depended on the degree and its leading coefficient.

1. If degree is even and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

2. If degree is even and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

3. If degree is odd and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

4. If degree is odd and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(a)

$f(x)=x^4$

Here, degree is even and leading coefficient is positive.

$f(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$f(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(b)

$g(x)=-x^4$

Here, degree is even and leading coefficient is negative.

$g(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$g(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(c)

$h(x)=x^3$

Here, degree is odd and leading coefficient is positive.

$h(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$h(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(d)

$k(x)=-x^3$

Here, degree is odd and leading coefficient is negative.

$k(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$k(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

4 0

3 years ago

Need help on this question

Aloiza [94]

I hope this helps you

4 0

3 years ago

What is the product of (4x+3)(-2x-5)

yuradex [85]

Use the FOIL method

First 4x × -2x = -8x^2
Outside 4x × -5 = -20x
Inside 3 × -2x = -6x
Last 3 × -5 = -15

-8x^2 - 20x - 6x -15 =

Combine like terms

-8x^2 -26x -15

8 0

4 years ago

Read 2 more answers

Help please because i am very dumb

Sloan [31]

A) 7000
B) 20000
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3 years ago

Q # 7 please solve. the math

aleksandr82 [10.1K]

The first choice is the correct answer
12 in by 22 in by 4 in

the explanation is as shown in the figure
The dimension will be x , 20 - 2x , 30 -2x

the volume= v = x(20-2x)(30-2x) = 4x³ - 100x² + 600x
differentiating with respect to x and equating to zero
dv/dx = 12x² - 200x + 600 = 0
solve for x using calculator
x = 12.7 (unacceptable) or x = 3.92 ≈ 4

∴ The dimension will be 4 , 12 , 22

7 0

3 years ago

Read 2 more answers