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drek231 [11]
3 years ago
9

Mr. smith earns 6% commission on every house he sells. if he earns $9,000, what was the price of the house?

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0
150000 because 9000/6*100=150000
S_A_V [24]3 years ago
3 0

Answer:

Price of the house was $150000.

Step-by-step explanation:

Let Mr Smith sells the house worth $x.

If he earns 6% as a commission on this property then commission will be = 6% of $x

Commission = $(0.06x)

This commission was $9000.

9000 = (0.06x)

x = \frac{9000}{0.06}

x = $150000

Therefore, price of the house was $150000.

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Write a polynomial if least degree with roots 9 and -6
klio [65]

Answer:

x² -3x  - 54

Step-by-step explanation:

given roots of a polynomial are 9 and -6

this means that (x-9) and (x+6) are factors of the polynomial.

To get the polynomial with the least degree, simply multiply the two factors to obtain a quadratic expression (degree 2)

(x-9) (x+6)

= x² + 6x -9x -54

= x² -3x  - 54

8 0
3 years ago
How many sides does a regular polygon have if one exterior angle is 1 degree
Mariulka [41]

Answer:

The number of sides are 360

Step-by-step explanation:

We are given

exterior angle is 1 degree

Firstly, we will find interior angle

interior angle = 180 - exterior angle

we can plug value

interior angle = 180 - 1

interior angle = 179

now, we can use formula

\frac{180(n-2)}{n}=\theta

now, we can plug angle

\frac{180(n-2)}{n}=179

now, we can solve for n

180\left(n-2\right)=179n

180n=179n+360

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So,

The number of sides are 360


5 0
3 years ago
Which of the following inferences can be made using the dot plots?
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3 years ago
the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant
Tamiku [17]

Answer:

The rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters is 24\pi \:\frac{cm^3}{s}

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

  • \frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • \frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • The volume of a cone of radius r and height h is given by V=\frac{1}{3} \pi r^2 h

We want to find the rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]

Substituting the values we know into the above formula:

\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}

5 0
4 years ago
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