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Bumek [7]
3 years ago
7

What is the answer to 2(r+y)

Mathematics
2 answers:
katrin [286]3 years ago
8 0

Answer: 2r + 2y

Step-by-step explanation:

AveGali [126]3 years ago
3 0
The answer: 2r + 2y

Why: distributing
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Which sentence is true about an equiangular triangle?
atroni [7]

Answer:

E.

Step-by-Step Answer

From the name <em>Eqiangular </em>you can tell from the name that it means equal and angles so your answer would be E. All angles have the same measure.

5 0
3 years ago
Josh bought a tv priced at $200, the cashier said taxes would be 10%.What is the total price he paid after his taxes
Gnesinka [82]

Answer:

<em>I believe the answer is $180 if then I'm not really sure</em>

<em />

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve each equation.
Elden [556K]

Answer:

1) x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2) x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3) p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4) y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

Step-by-step explanation:

The quadratic formula is given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}

x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}

x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}

p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}

y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

8 0
4 years ago
Miss Allen read for 3/4 of an hour less than the student who read the most. How long sis Miss Allen read for?
kolbaska11 [484]

Answer:

See Explanation

Step-by-step explanation:

Given

Allen = \frac{3}{4}hr less than the most hour

Required

Hours read by Miss Allen

The question is incomplete, as the hours read by each student is not given.

To solve this, I will assume that the longest hours read by a student is x.

So, the expression for Miss Allen will be:

Allen = x - \frac{3}{4}hr

Assume that x = 1hr

The expression becomes

Allen = 1hr - \frac{3}{4}hr

Take LCM and solve

Allen =\frac{4 - 3}{4}hr

Allen =\frac{1}{4}hr

7 0
3 years ago
Sss, asa, sas i don't get it
ohaa [14]
I hope this helps you



SSS Side-Side-Side


ASA Angle-Side-Angle


SAS Side-Angle-Side
5 0
3 years ago
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