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Gekata [30.6K]
3 years ago
8

LAST ONE!! (:

Mathematics
1 answer:
joja [24]3 years ago
4 0
First you find how much the shape has dilated. To d ok that you divide the size of the size already given to you from the bigger shape from the same did if the smaller shape. So 58÷6=9.7. The shape grew by 9.7. To find x you use the similar side of the other shape again and multiy that size by 9.7. So 9.7×3=29.1

x=29.1
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Answer: Ordinal measurement scale

Step-by-step explanation:

In ordinal measurement scale the order of values or variables are very important. Just as in the case above, the rating from 1-3 is according to the order of it's importance.

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7 0
3 years ago
Please help!! algebra<br> Find each value<br> 1. ∛x³<br> 2. 6³<br> 3. 10³
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5 0
3 years ago
The washer in the image has an inner diameter of 1/4 inch. The outer diameter measures 3/4 inch, and the washer is 1/4 inch thic
Talja [164]

Answer:

  0.14 lb . . .  closest choice is 0.11 lb

Step-by-step explanation:

The inside and outside radii are 1/8 in and 3/8 in, respectively. Then the area of the top of the washer is ...

  A = π(R² -r²) = π((3/8)² -(1/8)²) = π(9/64 -1/64) = π/8 . . . square inches

The height of the stack of 5 washers will be 5×(1/4 in) = 5/4 in. So, the volume of material in the stack of washers is ...

  V = Bh = (π/8)(5/4) = 5π/32 . . . cubic inches

The weight of material is the product of volume and density, so is ...

  W = (5π/32 in³)(0.285 lb/in³) ≈ 0.1399 lb ≈ 0.14 lb

_____

<em>Comment on the question</em>

Since this answer does not correspond to any of the offered choices, we suggest you ask your teacher to work this out for you. We suspect they will have difficulty justifying any of the answer choices shown here. (0.11 lb corresponds to 4 washers, not 5.)

5 0
4 years ago
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horrorfan [7]
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4 0
3 years ago
Read 2 more answers
A fair die is rolled 5 times. What is the probability that a 3 is obtained on at least one of the rolls? Round your answer to th
Lerok [7]

Answer:

0.200

Step-by-step explanation:

The probability of obtaining a 3, in one roll of a fair die is 1/6.

Now, we have 5 rolls.

We now want to know the probability of a 3 showing up in at least one of the rolls.

This simply mean, we add the probabilities of three showing one time plus probability of three showing in 2 of the rolls e.t.c

This means we can have 3 showing up to 5 times.

We add the probabilities as follows:

(1/6) + (1/6)^2 + (1/6)^3 + (1/6)^4 + (1/6)^5 = 0.199974 = 0.200

3 0
3 years ago
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