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3 years ago

Find the exact value of tan 0

Mathematics

2 answers:

sineoko [7]3 years ago

7 0

Tan(0)=sin(0)/cos(0)=0/1=0

allsm [11]3 years ago

3 0

Tan (0) is equal to 0
Sin (0) = 0
Cos (0) = 1

Tan = Sin/Cos
That means that Tan (0) = 0/1 or 0

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Lola gets two 20-minute breaks at work each day. She works 5 days a week. How much time does she spend on break each week?

Maslowich

Answer:

200 minutes / 3 hours & 20 minutes.

Step-by-step explanation:

This is quite simple.

First, since we know that Lola takes two 20 minute breaks at work each day, let's multiply 20 and 2.

20 × 2 = 40

This means she is on break for a total of 40 minutes each day.

Finally, let's take that 40 and multiply it by 5.

40 × 5 = 200

This means she spend 200 minutes (3 hours & 20 mins) on break each week.

8 0

3 years ago

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An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

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adoni [48]

5*2=25

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Katen [24]

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In this case, the equation is y = 1.8x.
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tigry1 [53]

Answer:

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Step-by-step explanation:

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