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velikii [3]
3 years ago
12

Find the mid-point of the line segment joining the points (10, 13) and (-7, 7)? ​

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

(3/2,10)

Step-by-step explanation:

Mid point is ((10-7)/2,(13+7)/2)=(1.5,10)

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Help me please !!!!!
EastWind [94]

no it can't

if u look closely at other numbers like 5 4 and 3,they can be multiplied 2 to give 10 ,6 and 8

but 10×2 isn't 12

it's 20

so it's not possible

plssss mark brainliestt

8 0
2 years ago
Ms sling deposited 850 in a savings account that paid 4.25% simple interest. What was the balance in her account at the end of 2
andrezito [222]
777.75

after 2 years. Because 4.25 is equal to .0425 then times that by the number.
5 0
3 years ago
Find the perimeter of the triangle defined by the coordinates (9, 0), (-5, 0), and (-10, 6). (Round to nearest tenth)
eduard
The perimeter is 41.7.

We first find the distance between each vertex using the distance formula:
d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}
\\
\\=\sqrt{(0-0)^2+(-5-9)^2}=\sqrt{0^2+(-14)^2}=\sqrt{196}=14
\\
\\d=\sqrt{(6-0)^2+(-10--5)^2}=\sqrt{6^2+(-5)^2}=\sqrt{36+25}=\sqrt{61}
\\=7.81
\\
\\d=\sqrt{(6-0)^2+(-10-9)^2}=\sqrt{6^2+(-19)^2}=\sqrt{36+361}=\sqrt{397}
\\=19.92

We now find the perimeter by adding all of the side lengths:
14+7.81+19.92 = 41.73 ≈ 41.7
7 0
3 years ago
A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at th
Mrac [35]

Answer:0.246ft/s

Step-by-step explanation: when the the worker starts moving and stops 10 feets away from lateral rope connecting the load, it forms a right angle triangle as see in the pix.

V = s/t ... equ 1

S= distance traveled by worker while pulling the rope = 10 ft

V = velocity of worker = 2ft/s

T = time taken the worker to move 10 ft = time taken for the load to move up = 5seconds

Use Pythagoras theorem to determine distance from pulley to new position of worker

Square root of (40^2 + 10^2) = 41.23ft

Distance traveled by load = D = 41.23 - 40

=1.23ft

Speed of load = D/ t...equ2

Substituting D and the into equ2

S.l = speed of load = 1.23/5 =0.246ft/s

4 0
3 years ago
On a graph of the function f(x)=2x+1 what is the range value when the domain value is 2?
harina [27]
The domain 2 would be plugged in as f (2)=2x+1 which equals 5
4 0
3 years ago
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