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velikii [3]
3 years ago
12

Find the mid-point of the line segment joining the points (10, 13) and (-7, 7)? ​

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

(3/2,10)

Step-by-step explanation:

Mid point is ((10-7)/2,(13+7)/2)=(1.5,10)

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
To convert 12 yards to inches, you would use the ratio .36inches/1 yard true or false ?
Taya2010 [7]
False. It's 36 not .36 and you would just do 12x36 since 36 inches is 1 yd. But if you want to make it complicated just do 12/1 times 36/1 which still equals 432.
8 0
3 years ago
Am in 8 groups. I am larger than 50. I have 7 in each of my groups. What product am i?
Sergio [31]

Answer:

56

Step-by-step explanation:

8 times 7=56

3 0
3 years ago
Find the interest rate needed for the sinking fund to reach the required amount. Assume that the compounding period is the same
Maslowich

Answer:

so rate is 4.72 %

Step-by-step explanation:

Given data

time (t) = 5 year  = 5×4 = 20 quarterly

amount = $27456

principal = $1225

to find out

interest rate (r)

solution

we use here amount formula that is

amount = principal ((1+r)^{t} -1 ) / r      .....................1

put all value principal , amount and time in equation 1 and we get rate

rate is r/4 because it is quarterly payment

amount = principal ((1+r/4)^{t} -1 ) / r/4

27456 = 1225 ((1+r/4)^{20} -1 ) / r/4

((1+r/4)^{20} -1 ) / r/4  = 27456/ 1225

((1+r)^{20} -1 ) / r  = 27456/ (1225 × 4)

((1+r)^{20} -1 ) = r 27456/ (1225 × 4)

now by the tvm solver and amount  $27456

graph value

we get r = 0.0472

so rate is 4.72 %

5 0
3 years ago
Read 2 more answers
2x+3y=6 what is the Solution
serg [7]

Answer:

x = 3- 3y/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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