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valina [46]
2 years ago
5

A square is divided by its four lines of symmetry. Triangles of different sizes are formed. How many total triangles are formed?

Mathematics
2 answers:
ss7ja [257]2 years ago
4 0
If you're only counting the smallest triangles, then 8.

If you're counting all possible triangles including triangles made of other triangles, then 16. Each diagonal gives 2, the combined diagonals give 4, and the unit triangles give 8 for a total of 2 + 2 + 4 + 8 = 16.
RoseWind [281]2 years ago
3 0
If we divide a square by it's 4 lines of symmetry, we can see that their are 8 single triangles, 4 double triangles, and 4 quadruple triangles. 8 + 4 + 4 = 16
There should be a total of 16 triangles. Hope this helps!
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The shampoo Eva likes to use costs $6 for a 24-ounce bottle. The conditioner she likes to use costs $12 for a 30-ounce bottle. H
lutik1710 [3]

Answer:

0.15

Step-by-step explanation:

6 divided by 24 equals 0.25

12 divided by 30 equals 0.4

0.4 minus 0.25 is 0.15

8 0
3 years ago
What is -3x-32=-2(5-4x)
san4es73 [151]

Answer:

x=−2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3x−32=−2(5−4x)

−3x+−32=(−2)(5)+(−2)(−4x)(Distribute)

−3x+−32=−10+8x

−3x−32=8x−10

Step 2: Subtract 8x from both sides.

−3x−32−8x=8x−10−8x

−11x−32=−10

Step 3: Add 32 to both sides.

−11x−32+32=−10+32

−11x=22

Step 4: Divide both sides by -11.

−11x

−11

=

22

−11

5 0
3 years ago
Read 2 more answers
Find, leave your answers in terms of pie,
Yuri [45]
Area of square = 10x10
= 100
area of circle = pi(r)^2
= pi (5)^2
=25pi

area of shaded = 100 -25pi

circumference of circle = 2pi (r)
= 2pi(5)
= 10pi

perimeters of shaded = 10pi + 10 + 10
= 10pi +20
8 0
1 year ago
That’s what I need to know to set it up plzzzzss help
AURORKA [14]
3×(60+7)
(3×30) + (3×7)
90 + 21 = 111
7 0
3 years ago
Read 2 more answers
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
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