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Radda [10]
3 years ago
7

Graph. y−5=4/3(x−5) Please help fast

Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

Slope:  4/3.  Point on line:  (8,9)

Step-by-step explanation:

Compare the given y−5=4/3(x−5) to

                                 y-k=m(x-h).  In this case, (h,k) is a point on the graph.

Thus, h = 5 and k = 5, and that point is (5,5).  Plot a black dot there.  Now make use of the slope, (4/3), to find another point on the line:

With your pencil point starting at (5,5), move it 3 units to the right, and from there, 4 units up.  Put another black dot there.  

Now draw a straight line through these two points (5,5) and (8,9).  Done.  

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PLE help ASAP!
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Answer:

The time it would take the element to decay to 28 grams is approximately 22.5 minutes

Step-by-step explanation:

The give half life of element X = 6 minutes

The given initial mass of the radioactive element X = 390 grams

The mass of the element X after decay = 28 grams

The function that represent the decay of element X is given as follows here;

y = a \cdot (0.5)^{\dfrac{t}{h} }

Which is of the form;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

Therefore;

h = 6 minutes = The time duration of the half life

a = N₀ = The initial mass = 390 g

N(t) = The final mass = 28 g

t = The time it takes the element to decay

Plugging in the values gives;

28 = 390 \times(0.5)^{\dfrac{t}{6} }

(0.5)^{\dfrac{t}{6} } = \dfrac{28}{390}

Therefore;

\dfrac{t}{6} \times ln\left(0.5} \right) = ln \left(\dfrac{28}{390} \right)

t/6 = ln(29/390)/ln(0.5)

t = 6 ×  ln(29/390)/ln(0.5) ≈ 22.496

Given the answer to the nearest tenth of a minute, the time it would take the element to decay to 28 grams, t ≈ 22.5 minutes.

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3 years ago
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Since angles 3 and 4 are supplementary, added together they'll = 180 degrees: 4x + 7x = 180.

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