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mafiozo [28]
3 years ago
11

If the retail price is $30,863 how much did the customer save ?

Mathematics
2 answers:
Natali5045456 [20]3 years ago
6 0
Give more info i dont understan.


Nadusha1986 [10]3 years ago
4 0
Well whats the whole question?

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Based on the diagram shown, find θ to the nearest degree.
sattari [20]

Answer:

  θ = 38°

Step-by-step explanation:

The lower right triangle is congruent to the upper left triangle, so we have θ and 20° being the two acute angles in the triangle. The law of sines tells you ...

  sin(θ)/9 = sin(20°)/5

  sin(θ) = (9/5)sin(20°)

  θ = arcsin(9/5·sin(20°)) ≈ 38°

___

Another solution to the triangle is θ = 180° -38° = 142°. The diagram clearly shows θ as an acute angle, so we take this second solution to be extraneous.

8 0
3 years ago
Write in figures;Nine million twenty thousand four hundred and six and twenty seven thousandths.​
Rzqust [24]

Answer:

9,020,406.27

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
3 years ago
a first class postage stamp was $0.02 in 1885. the same first class postage stamp in 2006 was $0.39. what is the percent of incr
Eddi Din [679]

The price was increased by $0.37 just subtract

5 0
3 years ago
Please help this is too hard
Tju [1.3M]

Answer:

idk help

Step-by-step explanation:

6 0
2 years ago
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