We have the following functions: log2x=5 log10x=3 log4x=2 log3x=1 log5x=4 Let's rewrite each function to solve for x: x=2^5=32 x=10^3=1000 x=4^2=16 x=3^1=3 x=5^4=625 Answer: Matching each function with the solution we have: log2x=5 ----------->32 log10x=3---------->1000 log4x=2------------>16 log5x=4------------>625
i suppose that t is an exponent. so let: v(t)=final prize of the scooter...t=time in years.....p=initial prize of the scooter . r= rate of depreciation per year so v(t)=p(1-r)^t....
