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maks197457 [2]
3 years ago
13

If possible, use the Law of Detachment to draw a conclusion from the two given statements. If not possible, write not possible.

Statement 1: If x = 7, then 7x – 2 = 47. Statement 2: x = 7
Mathematics
2 answers:
Julli [10]3 years ago
5 0

Answer:

x=7

Step-by-step explanation:

bogdanovich [222]3 years ago
3 0
Whats 9 + 10? 21!          U stupid Im not
 
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Estimate the sum of 703 + 620
Natalija [7]
When you estimate, you round each number, the add.
We round them to 
700+620, which is 1320
So our non estimated answer is 1323
But our estimated answer is 1320
7 0
3 years ago
Can you help me solve this?​
yuradex [85]

Answer:

Abraham Lincoln

Step-by-step explanation:

hes the 16th president, duh

7 0
2 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
A team won 9 of its first 12 games. At that rate, how many games will the team win if it plays 64 games in all?
Feliz [49]
9 out of 12 = 9/12 which can be simplified to 3/4.  So the team wins 3/4 of its games.  3/4 of 64 = 64 divided by 4 = 16.  16 x 3 = 48. 
3 0
3 years ago
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What is the answer to 8y^2-200z^2?
leva [86]

Answer:

Step-by-step explanation:

4 0
3 years ago
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