PLEASE HELP ME WITH ALL THOSE QUESTIONS ASAP PLEASE!!!!
2 answers:
You might be interested in
Rather than use that formula, look at the attachment and use the 4th equation.
Ending Amount = Beginning Amount / 2^n
where "n" is the number of half-lives. "n" = elapsed time / half-life
(Is 934 the beginning amount? Let's say it is.)
for 40 years, n=40/30 = 1.3333333...
Ending Amount = 934 / 2^1.3333333...
Ending Amount = 934 / <span> <span> <span> 2.5198420998 </span> </span> </span>
Ending Amount = <span> <span> <span> 370.66 grams
</span></span></span>
for 100 years, n=100/30 = <span> <span> <span> 3.333333 </span> </span> </span> ...
Ending Amount = 934 / 2^<span> <span> 3.333333 </span> </span> ...
Ending Amount = 934 / <span> <span> <span> 10.0793683992 </span> </span> </span>
Ending Amount = <span> <span> <span> 92.66 grams
Source:
http://www.1728.org/halflife.htm
</span></span></span>
Ending Amount = Beginning Amount / 2^n
where "n" is the number of half-lives. "n" = elapsed time / half-life
(Is 934 the beginning amount? Let's say it is.)
for 40 years, n=40/30 = 1.3333333...
Ending Amount = 934 / 2^1.3333333...
Ending Amount = 934 / <span> <span> <span> 2.5198420998 </span> </span> </span>
Ending Amount = <span> <span> <span> 370.66 grams
</span></span></span>
for 100 years, n=100/30 = <span> <span> <span> 3.333333 </span> </span> </span> ...
Ending Amount = 934 / 2^<span> <span> 3.333333 </span> </span> ...
Ending Amount = 934 / <span> <span> <span> 10.0793683992 </span> </span> </span>
Ending Amount = <span> <span> <span> 92.66 grams
Source:
http://www.1728.org/halflife.htm
</span></span></span>
Answer:
0.9999
Step-by-step explanation:
Let X be the random variable that measures the time that a switch will survive.
If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by
So, the probability that a switch fails in the first year is
Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.
Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and
where
equals combinations of 100 taken k at a time.
The probability that at most 15 fail during the first year is