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3 years ago

Find the distance between the point (6,3) and(6,-7)

Mathematics

2 answers:

natima [27]3 years ago

5 0

The answer would be -10 down

lawyer [7]3 years ago

5 0

10 units

Since the x- coordinates of the 2 points are equal, that is 3 then the distance between the 2 points is the difference in the y- coordinates.

distance = 3 - (- 7) = 3 + 7 = 10

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Help. I just started this

inn [45]

X is (4/3,0)
Y is (0,-4/5)

Hope that helps!

7 0

3 years ago

A circle has a center of (5,-5) and goes through (6,-2). What is the radius?

Fittoniya [83]

Start with the equation of a circle whose center is at (h,k) and whose radius is r:

(x-h)^2 + (y-k)^2 = r^2

Substituting the given coordinates of the center:

(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2

Substituding the given coordinates of a point (6,-2) on the circle:

(6-5)^2 + (-2+5)^2 = r^2

Simplifying:

1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).

6 0

3 years ago

The function y=7500(1.08)t represents the value y of an investment after t years. What is the value of the investment after 6 ye

boyakko [2]

Answer:

The answer is 48600, but I'm not entirely sure if it correct.

From what I know, if I were to see ¨y=7500(1.08)t¨, we could have to substitute the t with the number of years. Looking like this, ¨y=7500(1.08) x 6¨.

The reason I don know if my answer is correct or not since I don know if you have the t next to 1.08 to represent that or to simply multiply the property of it with 6 (the number of years).

So I tried...

Step-by-step explanation:

4 0

3 years ago

The number of errors in a textbook follow a poisson distribution with a mean of 0.01 errors per page. what is the probability th

neonofarm [45]

Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1

It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.

Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.

The Poisson distribution has a PMF (probability mass function)

$P(k):=\frac{\lambda^ke^{-\lambda}}{k!}$
with λ = 1
=>
$P(0):=\frac{1^0e^{-1}}{0!}=0.3678794$
$P(1):=\frac{1^1e^{-1}}{1!}=0.3678794$
$P(2):=\frac{1^2e^{-1}}{2!}=0.1839397$
$P(3):=\frac{1^3e^{-1}}{3!}=0.0613132$
=>
$P(k$
or
P(k<=3)=0.9810 (to four decimal places)

3 0

3 years ago

4/5 = 28/x <br><br> x= <br> i need to know what x =

ella [17]

Answer:

Hello! :) have a good day!

x = 35

4/5 = 28/35

5 0

3 years ago