Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Given:
Consider the number as <em>x</em>.
The objective is to represent algebraic expression for, 2 is subtracted from the square of a number.
Explanation:
Since the number is given as <em>x</em>, the square of the number can be represented as,

Now, subtract 2 from the above expression,

Hence, the required expression is x²-2.
Answer:
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