Answer:
Step-by-step explanation:
since there are 205 calories in 5 crackers we can represent this as
205/5
we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker
so
cross multiply
5x=205
divide by 5 on both sides
x=41
41 calories in 1 cracker
Number line:
The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
The greatest common factor is 4
The number is = 10x+y
if reverse the digits, the number is: 10y+x
The sum fo its digits is = x+y=5
I suggest this system of equations:
(10y+x)-(10x+y)=27 ⇒9y-9x=27
x+y=5
We can solve this system of equations by equaliztion method
x=5-y
9y-9(5-y)=27
9y-45+9y=27
18y=27+45
18y=72
y=72/18
y=4
x=5-y
x=5-4=1
The number is: 10x+y=10(1)+4=14
Answer: the number is 14
Answer:
m∠1 = 60°
m∠2 = m∠4 = 39°
m∠3 = m∠5 = 21°
Step-by-step explanation:
ΔWXY is a equilateral angle,
Therefore, all angles of the the triangle are equal in measure.
m∠W + m∠X + m∠Y = 180°
3m∠W = 180°
m∠W = 60°
Since, ΔWZY is an isosceles triangle,
m∠3 = m∠5
m∠3 + m∠Z + m∠5 = 180°
m∠3 + 138° + m∠3 = 180°
2m∠3 = 180 - 138
m∠3 = 21°
Therefore, m∠3 = m∠5 = 21°
Since, m∠2 + m∠3 = 60°
m∠2 = 60 - 21
= 39°
Since, m∠4 + m∠5 = 60°
m∠4 = 60 - 21
= 39°
m∠1 = 60°
