The sum of 32 and 5 times a number is 17

Mathematics

1 answer:

Mrrafil [7]3 years ago

7 0

"Sum of 32 and 5 times a number " translates to:

(32 + 5) × n

Then, it says "is 17"

So, (32 + 5) × n = 17. Let's solve!

32 + 5 = 37

37 × n = 17

To find n, we just divide 17 by 37. However, that equates to a repeating decimal, so it is best to put the answer as:

$\frac{17}{37}$

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Anybody know the answer I need help. Please

Evgen [1.6K]

Answer:

$\dfrac{p^2+9p+2}{p^2-49}$

Step-by-step explanation:

Problems like this require that you recognize that the denominator of the right term is a factor of the denominator of the left term. That is, you're supposed to know how to recognize and factor the difference of two squares.

$\dfrac{5-p}{49-p^2}+\dfrac{p+1}{p-7}=\dfrac{p-5}{p^2-49}+\dfrac{p+1}{p-7}\\\\=\dfrac{p-5}{(p-7)(p+7)}+\dfrac{p+1}{p-7}\cdot\dfrac{p+7}{p+7}\\\\=\dfrac{(p-5)+(p+1)(p+7)}{(p-7)(p+7)}=\dfrac{p-5+p^2+8p+7}{p^2-49}=\dfrac{p^2+9p+2}{p^2-49}$