Which expression is equivalent to 4(3−6x)+x ?

Zanzabum

If you have a quadratic equation in the form ax2+bx+c
Step 1) Determine the product of AC (the coefficients in a quadratic equation)Step 2) Determine what factors of a⋅c sum to bStep 3) "ungroup" the middle term to become the sum of the factors found in step 2Step 4) group the pairs.

3 0

3 years ago

Read 2 more answers

((a^2m+n)(b^n-2m))/((a^n-m)(b^2m-n))

Novosadov [1.4K]

Answer:

SCREEEEEEEEeEEEEeeEEeeEEEEEe

Step-by-step explanation:

7 0

2 years ago

A park has a large circle painted in the middle of the playground area. The circle is divided into 4 equal sections, and each se

oee [108]

First you need to find the area of the whole circle. $\pi r^{2}$
The radius is given as 10, so just insert 10 into the equation of the area of a circle equation.
$Area = \pi 10^{2} Area = 100 \pi$
Putting $\pi$ after the 100 because that is what is commonly done.

Because the circle is then being split into 4 equal sections, we need to find 1/4 of the area of the whole circle to find the area of one of these sections.

Since the area of the whole circle is $100 \pi$ then we just divide that by 4,
leaving us with 25 $\pi$ and that is our final answer

3 0

2 years ago

DIscrete Math

Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

$f : X \rightarrow Y$ is surjective implies there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ .
If there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ , then $f : X \rightarrow Y$ is surjective

Let us start by the first implication.

Our hypothesis is that the function $f : X \rightarrow Y$ is surjective. From this we know that for every $y\in Y$ there exist, at least, one $x\in X$ such that $y=f(x)$ .

Now, define the sets $X_y = \{x\in X: y=f(x)\}$ . Notice that the set $X_y$ is the pre-image of the element $y$ . Also, from the fact that $f$ is a function we deduce that $X_{y_1}\cap X_{y_2}=\emptyset$ , and because $f$ the sets $X_y$ are no empty.

From each set $X_y$ choose only one element $x_y$ , and notice that $f(x_y)=y$ .

So, we can define the function $h:Y\rightarrow X$ as $h(y)=x_y$ . It is no difficult to conclude that $f\circ h(y) = f(x_y)=y$ . With this we have that $f\circ h=1_Y$ , and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function $h:Y\rightarrow X$ such that $f\circ h=1_Y$ .

Take an element $y\in Y$ , then $f\circ h(y)=y$ . Now, write $x=h(y)$ and notice that $x\in X$ . Also, with this we have that $f(x)=y$ .

So, for every element $y\in Y$ we have found that an element $x\in X$ (recall that $x=h(y)$ ) such that $y=f(x)$ , which is equivalent to the fact that $f$ is surjective. Therefore, the prove is complete.

3 0

2 years ago

2 Richard and Jason each begin filling pools at the same time.

alina1380 [7]

The quantity of the liquid in Richard's tank after 20 minutes will be 120 gallons and in Jason's tank will be 240 gallons.

<h3>What are gallons?</h3>

A gallon is a British unit which is used for the measurement of liquids that is equal to eight pints. In Britain, it is equal to about 4.546 litres. In America, it is equal to about 3.785 litres.

It is given in the question that:-

Richard fills his pool at a rate of 6 gallons per minute.

Jason's pool already contains 200 gallons, and he fills it at a rate of 2 gallons per minute.

After 20 minutes the amount of liquid in the tank will be:-

For Richard = 6 gallons per minute. x 20 minutes= 120 gallons

For Jason= 2 gallons per minute x 20 =40 gallons

Jason has 200 gallons already in the tank

So it will become = 200+24=240 gallons.

Hence quantity of the liquid in Richard's tank after 20 minutes will be 120 gallons and in Jason's tank will be 240 gallons.

To know more about Gallons follow

brainly.com/question/16691874

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7 0

2 years ago