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3 years ago

find the domain and range of the relation (-3,3),(-3,2),(-3,1)(-3,0).Then determine whether the relation is a function

1 answer:

4 0

The domain is the x value: (-3)
The range are the y values: (0, 1, 2, 3) in order from least to greatest
No this is not a function because that value of x is "reused". You can "reuse" a y value with different x values but you can't reuse an x value ever, even if the y's are different. x's cannot be the same

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Find the distance between the points (1,3) and (5,0).

Irina18 [472]

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I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

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3 years ago

What is the value of x in the equation below?

belka [17]

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$

$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
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$take \space\ ln \space\ of \space\ both \space\ sides$
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5 0

3 years ago

Read 2 more answers

If the measure of arc XY plus the measure of a arc YZX equals 360 and the arcs dont overlapp then what do the arcs form?

gavmur [86]

Check the picture below.

6 0

3 years ago

ive males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five

Nonamiya [84]

Answer:

a c d

.............................................

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3 years ago

Recently, a random sample of 13-18 year olds was asked, "How much do you currently have in savings?" The data in the table re

Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

$\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]$

This is an example of grouped data, where a range of values is given rather than a single data point. First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0

3 years ago