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grin007 [14]
3 years ago
5

What is the surface area of the rectangular prism below?

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0

Answer:

490 units squared

Step-by-step explanation:

iragen [17]3 years ago
3 0

Answer:

The correct answer is option C.  490 units ²

Step-by-step explanation:

Area of cuboid = 2(lb + bh + lh)

From the figure we can see that a rectangular prism.

<u>To find the surface area of prism</u>

Here l = 14 units

b = 7 units and h = 7 units

Surface area = 2((14 * 7) + (7 * 7) + (14 * 7))

= 490 units ²

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4m/4 < -8/4
Then reduce the expression by cancelling the common factors. 
m < -8/4
Simplify the right side of the equation.
Divide 8 by 4 to get 2.
m < -1*2
Multiply -1 by 2 to get -2
m < -2


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3 years ago
Write the ordered pair that represents yz. Then find the magnitude of yz.<br> Y(-2, 5), z(1,3)
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Answer:

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Step-by-step explanation:

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4 years ago
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34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
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OlgaM077 [116]

Answer:

(0,1)

Step-by-step explanation:

The solution to a system of equations is where the two lines intersect. Algebraically, you could solve this by setting the equations equal to each other.

I hope this helps!

7 0
4 years ago
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