The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.
If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.
side a = side b
Using Pythagorean theorem, c^2 = a^2 + b^2
h^2 = a^2 + b^2 a = b
h^2 = 2a^2
a = h/√2
If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.
ΔABC and ΔADE are similar triangles.
a : b : h = a/2 : 4 : h/2
If a/2 = a/2, then b/2 = 4.
b/2 = 4
b = 8
If a = b, then a = 8.
If a = h/√2, then
8 = h/√2
h = 8√2
Solving for the perimeter,
P = a + b + h
P = 8 + 8 + 8√2
P = 16 + 8√2
P = 27.3137085
To learn more about midsegment: brainly.com/question/7423948
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Answer:
351.9 cubic in
Step-by-step explanation:
The volume of a cylinder is hr²π.
r is half the diameter, so 8/2 is 4.
Plug in your h and r and get:
7 * 4² * π
7 * 16 * π
112π
Multiply the π and you'll get about 351.9 cubic in
6.25 for each kids ticket and 11.75 for each adult ticket
The formula for the volume of a pyramid Is V = 1/3 Bh, where V is the volume, B is the area of the base, and h is the height of the pyramid. Cecilia
has a pyramid-shaped candle with a square base. The volume of the candle is 720 cm3 and the area of the base is 36 cm2
Answer:
19
Step-by-step explanation:
The markings on the triangle means that this is an equilateral triangle (All sides are the same length)
So, we can set the two equations we have equal to each other
4x + 7 = 3x + 10
x + 7 = 10
x = 3
Plug it into either equation
3(3) + 10 = 19
