Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
The factors of 56: 1; 2; 4; 7; 8; 14; 28; 56
The factors of 84: 1; 2; 3; 4; 6; 14; 28; 42; 84
GCF(56; 84) = 28
Answer: 3.5
Step-by-step explanation:
Answer:
9^6=531441
Step-by-step explanation:
To calculate ,on the Scientific calculator
-First press 9 marked on the set of numbers.
--Then go to the indices expression and press on it.
--After that press 6.
--You will get the value of 9^6=531441
Answer:
8.900 g/cm³
Step-by-step explanation:
The density of an object is given by:
ρ = 
ρ is the density.
M is the object's mass.
V is the object's volume.
Given values:
M = 222.50 g
V = 25.00 cm³
Substitute the given values into the equation and solve for ρ:
ρ = 222.50/25.00
ρ = 8.900 g/cm³
