Question

A certain bacteria is growing at a rate of 4 percent each day. If the culture of bacteria has 5,000 bacteria today, how many bacteria will be present 10 days from now?

Answer 1

This is the concept of exponential growth, To get the number of bacteria after 10 days we use the formula:
f(t)=ae^(kt)
where;
a=initial number=5000
k=constant of proportionality= 0.04
t=time=10 days
f(t)=future number
thus the number of bacteria in 10 days will be:
f(t)=5000e^(0.04*10)
f(t)=7,459.12
The answer is 7,459.12

Answer 2

We know that the culture of bacteria has 5,000 bacteria today.
Also : p = 4 %  = 0.04, and t = 10 ( 10 days from now )
The formula is:
A = P * ( 1 + p )^t
A = 5,000 * ( 1 + 0.04 ) ^10
A = 5,000 * 1.04^10
A = 5,000 * 1.48
A = 7,401
Answer: There will be 7,401 bacteria.