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3 years ago

What’s the answer ????

Mathematics

1 answer:

KonstantinChe [14]3 years ago

5 0

The answer is b. it is simply the only reasonable answer

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Please let me know all of the following that applies, thank you in advance.

kramer

Answer: A. EOA and DOS and also

B. SOE and DOA

Step-by-step explanation:

If you look at angle EOA without regarding line OB, you will notice that it is directly opposite to angle DOS.

The same applies for angle SOE and DOA so they are vertically opposite.

3 0

3 years ago

Whats the answer for 7^5/7^3=

Contact [7]

Answer:

7^2

Step-by-step explanation:

there is one law of exponent, where if you're dividing 2, and the base is the same, you can just subtract the exponents so-

4 0

3 years ago

Read 2 more answers

A bus travel 210 miles in three. Five hours assumed the distance travel is directly proportional to the time traveled right and

yarga [219]

God loves all of you, remember that oK. Thts really all u need in life <333 and 210m is

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2 years ago

graph the solution to the following system of inequalities y<-2x+7, y greater than or equal to 2x - 3

Alex777 [14]

Answer:

See attached diagram

Step-by-step explanation:

Graph the solution of the inequality $y$ First, draw the dotted line $y=-2x+7$ (dotted because the sign of the inequality is <). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (red part on the diagram).

Graph the solution of the inequality $y\ge 2x-3.$ First, draw the solid line $y=2x-3$ (solid because the sign of the inequality is ≥). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (blue part on the diagram).

The intersection of both regions is the solution of the system of two inequalities.

6 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago