1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd
a^2b^2+8ab−9ab−72
2. Collect the like terms
a^2b^2+(8ab−9ab)−72
3. Simplify
a^2b^2-ab-72
Hope this helps
Determining a car's depreciation over a ten year period is considered a bivariate.
<h3>What is a bivariate?</h3>
A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.
To learn more about depreciation, please check: brainly.com/question/25552427
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Answer:
Step-by-step explanation:
Graph: f(x) = 1 - ex
You meant f(x) = 1 - e^x, where ^ represents exponentiation.
First, graph the parent function y = e^x. The y-intercept of this graph is (0, 1), and the x-axis is the horizontal intercept. The graph begins on the left in Quadrant 2 and continues upward in Quadrant 1.
Next, reflect this graph in the x-axis, due to the - sign in f(x) = 1 - e^x. The y-intercept is (0, -1) and the horizontal asymptote is the x-axis.
Finally, translate the whole graph upward by 1 unit.
Let Jean's speed while running = x mph
Then Jean's speed while riding will be = x+9 mph
Distance covered by running = 8 miles
Distance covered by riding = 11 miles
Total time taken to complete the race = 1.5 hours
As, 
So, time for running= 
And time for riding= 
Equation becomes:
Now, multiply every term by 2x(x+9) to clear denominators:
Simplifying it we get
Solve the quadratic equation using formula
putting a=3 , b= -11, c= -144
we get (x - 9)(3x + 16) = 0
where x=9 and x=
Neglect the negative answer as speed cannot be negative, so x = 9 mph
Hence, Jean's running speed is 9 mph and riding speed is x+9 = 9+9 = 18 mph
Answer:
73.3
Step-by-step explanation:
50mi/h * 5280ft/mi * 1h/3600s = 220/3 = 73.3 ft/s
