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4 years ago

4539/51 estimate the quotient

Mathematics

1 answer:

ikadub [295]4 years ago

3 0

Answer: 89

Step-by-step explanation: 4359/51=89

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Which transformation maps the pre-image to the image?

Ede4ka [16]

Answer:

Reflection

Step-by-step explanation:

Because reflecting yourself in a mirror means pre image to image

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3 years ago

Can somebody plz report and ban CARDAA13 and CARIZASHINE

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Answer:

what did they do?

Step-by-step explanation:

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3 years ago

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Monica [59]

Expand f(z) into partial fractions:

$\dfrac1{z(z-2)} = \dfrac12 \left(\dfrac1{z-2} - \dfrac1z\right)$

Recall that for |z| < 1, we have the power series

$\displaystyle \frac1{1-z} = \sum_{n=0}^\infty z^n$

Then for |z| > 2, or |1/(z/2)| = |2/z| < 1, we have

$\displaystyle \frac1{z-2} = \frac1z \frac1{1 - \frac2z} = \frac1z \sum_{n=0}^\infty \left(\frac 2z\right)^n = \sum_{n=0}^\infty \frac{2^n}{z^{n+1}}$

So the series expansion of f(z) for |z| > 2 is

$\displaystyle f(z) = \frac12 \left(\sum_{n=0}^\infty \frac{2^n}{z^{n+1}} - \frac1z\right)$

$\displaystyle f(z) = \frac12 \sum_{n=1}^\infty \frac{2^n}{z^{n+1}}$

$\displaystyle f(z) = \sum_{n=1}^\infty \frac{2^{n-1}}{z^{n+1}}$

$\displaystyle \boxed{f(z) = \frac14 \sum_{n=2}^\infty \frac{2^n}{z^n} = \frac1{z^2} + \frac2{z^3} + \frac4{z^4} + \cdots}$

6 0

2 years ago

Simplify (3/8 - 6/4) - (9/16 - 3/4)

Y_Kistochka [10]

Answer:

-132

Step-by-step explanation:

24-24)-(144-12)

0-132

-132

8 0

4 years ago

Peter says, "If you subtract 19 from my number and multiply the difference by -3, the result is

Likurg_2 [28]

Answer:

Step-by-step explanation:

Let the peter's number be represented x

Given that

1. if you subtract 19 from my number

writing it mathematically it will be x -19

2. multiply the difference by -3

it can be written as

since difference is x-19

multiplied the difference with -3

-3(x-19)

3. the result is -21

-3(x-19) = -21

dividing both side by -3

-3(x-19)/-3 = -21/-3

x-19 = 7

adding 19 both sides

x-19 + 19 = 7 + 19

x = 26

Thus, peter's number is 26.

4 0

3 years ago