Answer:
22
Step-by-step explanation:
Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j
Pretend the addition 5 values is k,l,m,n,o
So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20
So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300
Now let's look at the first 10: We have their mean so we can write:
(a+b+c+d+e+f+g+h+i+j)/10=19
so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190
So that means using our first sum equation and our equation sum equation we have
190+k+l+m+n+o=300
k+l+m+n+o=300-190
k+l+m+n+o= 110
So the average of those 5 numbers mentioned in your problem is 110/5=22
<em>Greetings from Brasil...</em>
Solving this equation
<h2>-7.4 + E = 9.11</h2><h2>E = 16.51</h2>
Answer:
56 quizzes
Step-by-step explanation:
40 quizzes = 5 weeks
To find the unit rate of quizzes / week, we can divide both sides by 5
40/5 quizzes = 5/5 weeks
8 quizzes = 1 week
Multiply both sides by 7 to find the amount of quizzes in 7 weeks
8 * 7 quizzes = 1 * 7 weeks
56 quizzes = 7 weeks
Step-by-step explanation:
The tables rule is y = x²+x. Thus, the three missing boxes from top to bottom are 6, 5, and 2. Two other rows could be x = 13, y = 182, and x = 0, y = 0.
Hope it helps <3
<h2 /><h2>
<u>Question</u><u>:</u></h2>
<u>find the height of the cylinder whose volume is 1.54 cubic m and radius of the base is 70 cm</u>
Required diagram :

<h3>Solution :</h3>
For a cylinder having a radius r and a height h ;
Volume Of Cylinder :
Here , the radius of the cylinder is given as 70 cm and the volume is 1.54 m³ .
Converting ;
- 1 m³ = 1 × 10⁶ cm³ .
- > 1.54 × 10⁶ cm³ .
- > 1540000 cm ³.
- > π r² h = 1540000
- > 22/7 × 70 × 70 × h = 1540000
- > 22 × 10 × 70 h = 1540000
- > 15400 h = 1540000
- > h = 100 cm = 1 m.
<u>The</u><u> </u><u>height</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>cylinder</u><u> </u><u>is</u><u> </u><u>100cm</u><u>.</u><u>=</u><u>1m</u><u>.</u>