Let f(x) = x^2 + 4x - 31. for what value of a is there exactly one real value of x such that f(x) = a?
1 answer:
This value of "a" is exactly the y-coordinate of the vertex of the parabola
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Just do a square and do 124/4= 31 and then to get the area you do length multiplied by length which is 31 X 31 which equals 961m squared.
Answer:
9600400000000000 is in standard form
Answer:
just substitute the value of x as 1
f(x)=3(12)x+1
f(1)=3(12)(1)+1
f(1)=3(12)(1)+1
f(1)=36+1
f(1)=37
Answer:
A true
B false
C false
D true
Answer:
1
Step-by-step explanation:
3/11 *3/11
2nd 3/11 flips over. Then multiply. Then u get 33/33 which equals 1
