The perimeter "P" is equal to the length of the base of one triangle multiplied by the "n" number of triangles in the figure plus two times the length of another side. The equation for the perimeter is P = 5n + 14.
We are given triangles. The triangles are arranged in a certain pattern. The length of the base of each triangle is equal to 5 units. The length of the other two sides is 7 units each. We conclude that all the triangles are isosceles. We need to find the relationship between the number of triangles and the perimeter of the figure. Let the perimeter of the figure having "n" number of triangles be represented by the variable "P".
P(1) = 14 + 5(1)
P(2) = 14 + 5(2)
P(3) = 14 + 5(3)
We can see and continue the pattern. The relationship between the perimeter and the number of triangles is given below.
P(n) = 14 + 5n
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Answer:
Vertex: (2,-2)
Axis of symmetry: x=2
Step-by-step explanation:
The vertex is the maximum or minimum point of a quadratic, which we can see on the graph is (2,-2).
The axis of symmetry is the line about which the graph of the parabola is symmetric, which is the line x=2.
Answer:
my pfp
Step-by-step explanation:
the answer to everything is my pfp
Slope = -1/2 hope that helps.........
