We can express this number in the standard form, which is simply 15xyz+10xy+5x. Alternatively, we can factor a 5 or an x out, receiving 5(3xyz+2xy+x) or x(15yz+10y+5). However, the most effective factorization is to factor out 5x, for a result of 5x(3yz+2y+1).
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
Answer:
100.9
Step-by-step explanation:
The 10th place is the one one right after the decimal, in this case 9. Since there's a 0 next to the nine you don't have to change anything. Thus you get 100.9
Answer:
(a) 95% of people have an IQ score between 66 and 134.
(b) 32% of people have an IQ score of less than 83 or greater than 117.
(c) 16% of people have an IQ score greater than 117
Step-by-step explanation:
