Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Consider the following sets of sample data: A: $29,400, $30,900, $21,000, $33,200, $21,300, $24,600, $29,500, $22,500, $35,200,
Lana71 [14]
Answer:
CV for A = 21.8%
CV for B = 15.5%
Step-by-step explanation:
The formula for coefficient of variation is:
CV = Standard Deviation / Mean
So,
For A:
Mean = Sum/No. of items
= 391300/14
=$27950
and
SD = $6085.31
CV for A = 6085.31/27950 * 100
=21.77%
Rounding off to one decimal
CV for A = 21.8%
For B:
Mean = Sum/No. of items
= 43.58/11
=3.96
and
SD = 0.615
CV for B = 0.615/3.96 * 100
=15.53%
=15.5% ..
Y=mx+b
Mx is the rate of change
B is your starting point
Started with 1000, A
-200 is the rate of change, D
Answer: 2/6 or 33%
Step-by-step explanation: Hope this helps <3
Answer:
x=4.956 im pretty sure
Step-by-step explanation:
