Question

A rectangular garden has a perimeter of 172 feet. The length of the garden is 24 feet more than the width. What are the dimensions of the garden? (Recall the formula P = 2L + 2W.)
a.62 ft by 86 ft
c.55 ft by 79 ft
b.31 ft by 55 ft
d.74 ft by 98 ft

Answer 1

Given width is 24 less than length.
W=L-24
Perimeter = 2(W+L)=2(L-24+L)=4L-48 
But we're also given perimeter = 172'
Therefore 4L-48=172
solve for L
4L=172+48=220
L=55'
W=55-24 =  31'
Check: Perimeter = 2(W+L)=2(31+55)=2*86=172'  good!

Answer: The dimensions of the garden are 31' * 55'