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stich3 [128]
4 years ago
10

="if \: y = x {e}^{ {x}^{2} } " alt="if \: y = x {e}^{ {x}^{2} } " align="absmiddle" class="latex-formula">
prove \: that \:  \frac{ {d}^{2} y}{ {dx}^{2} } - 2x \frac{dy}{dx}  - 4y = 0
Good Luck for 50 points!​

Mathematics
1 answer:
dezoksy [38]4 years ago
3 0

Answer:

Hope it helps!

please mark me brainliest

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What is 4/3s-3≥5-4 please help :).
saveliy_v [14]

Let's solve your inequality step-by-step.

\frac{4}{3}s−3≥5−4

Step 1: Simplify both sides of the inequality.

\frac{4}{3}s−3≥1

Step 2: Add 3 to both sides.

\frac{4}{3}s−3+3≥1+3

\frac{4}{3}s≥4

Step 3: Multiply both sides by 3/4.

(\frac{3}{4})*(\frac{4}{3}s)≥(\frac{3}{4})*(4)


Answer: s≥3

5 0
3 years ago
Which step should be taken next to construct a line through point P perpendicular to BA?
Pavel [41]

Answer:

Refer picture enclosed

Step-by-step explanation:

Given is a line BA and a point P.  We have to construct a line perpendicular to BA through P.

Case I: P lies on the line BA

Without loss of generality assume BP is smaller than AP.

Cut an arc C on AB from P such that BP=CP

Now with B and C as centres draw arc up and down the line with more than half length of BC

Join the intersecting of arcs.  That line is the perpendicular for BA through P.

This is because of concurrency of two triangles above the line BC

Case2:

P lies outside the line.  Measure PB and cut an arc of BA with length PB

Let the point be C

Then CP=BP

NOw do as we did before the line with arcs more than 1/2 length of BC from B and C only down.  Join the point of intersection down with P.  This line will be perpendicular through P to BA




8 0
3 years ago
Read 2 more answers
Help with number 16 please.
erik [133]
All you have to do is add the exponets (4 and 2) to get 6

so the correct answer is 

A.6

hope I helped

5 0
3 years ago
Read 2 more answers
Which statement is true about the two lines whose equations are given below?
zloy xaker [14]

Answer:

They intersect but not perpendicular.

3 0
3 years ago
For funcitons f(x)=2x+3 and g(x)=-3x-2, please find (f∘g)(-1)
ratelena [41]

Answer:

\displaystyle (f\circ g)(-1) = 5

Step-by-step explanation:

We are given the two functions:
\displaystyle f(x) = 2x + 3\text{ and } g(x) = -3x - 2

And we want to find:
\displaystyle (f\circ g)(-1)

Recall that this is equivalent to:
\displaystyle (f\circ g)(-1) = f(g(-1))

Hence, find g(-1):
\displaystyle \begin{aligned} g(x) & = -3x - 2\\ \\ g(-1) & = -3(-1) - 2\\ \\ & = (3) - 2 \\ \\ & = 1 \end{aligned}

Substitute:
\displaystyle f(g(-1)) = f(1)

Find f(1):

\displaystyle \begin{aligned} f(x) & =  2x+ 3 \\ \\ f(1) & = 2(1) + 3 \\ \\ & = 5\end{aligned}

In conclusion:
\displaystyle (f\circ g)(-1) = 5

5 0
3 years ago
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