Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
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Answer:
C i think
Step-by-step explanation:
Answer:
(4,-7)
Step-by-step explanation: