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Grace [21]
3 years ago
11

A baseball team plays in a stadium that holds 56000 spectators. With the ticket price at $9 the average attendance has been 2500

0. When the price dropped to $7, the average attendance rose to 28000. a) Find the demand function p(x), where x is the number of the spectators. (Assume that p(x) is linear.)
Mathematics
1 answer:
Nana76 [90]3 years ago
5 0

Answer:

p(x) = 38500 - 1500x.

Step-by-step explanation:

The average attendance was 25000 when the ticket price at $9. The average attendance rose to 28000 when the price lowered to $7.

Therefore, if the demand function p(x) where, x is the value of each tickets is linear then we have p(9) = 25000 and p(7) = 28000.

Hence, the demand function will be given as

\frac{p(x) - 28000}{28000 - 25000} = \frac{x - 7}{7 - 9}

⇒ p(x) - 28000 = 1500(7 - x)

⇒ p(x) = 28000 + 10500 - 1500x

⇒ p(x) = 38500 - 1500x. (Answer)

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Answer:

a) System of equations will be:  x+y=500\: and\:5x+2y=1789

b) Number of adult tickets sold =  263

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Step-by-step explanation:

Let:

Number of adult tickets sold = x

Number of students tickets sold = y

a)

As Marc sold total 500 tickets, the expression will be: x+y=500

Student tickets cost $2 and adult tickets cost $5. Marc's sales totalled $1,789.

The expression will be: 5x+2y=1789

So, system of equations will be:  x+y=500\: and\:5x+2y=1789

b)

Solve the system to find value of x and y

Let:

x+y=500--eq(1)\\5x+2y=1789--eq(2)

Multiply equation 1 by 2 and subtract

2x+2y=1000\\5x+2y=1789\\-\:\:\:-\:\:\:\:\:\:\:\:\:-\\------\\-3x=-789\\x=\frac{-789}{-3}\\x=263

We get value of x = 263

Now finding value of y by putting value of x in eq(1)

x+y=500\\263+y=500\\y=500-263\\y=237

We get value of y = 237

Number of adult tickets sold = x = 263

Number of students tickets sold = y = 237

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