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2 years ago

Math help 30 points

Mathematics

1 answer:

mash [69]2 years ago

7 0

Again here we're using like terms

a) -2x² + 12x² = 10x² (they have the same term that's why I grouped them together)

-4x + 2x = -2x

13 - 25 = -12

So the final answer is 10x² - 2x -12

b) 7x² - (-7x²) = 7x² + 7x² or 14x²

4x - (-3x) = 4x + 3x or 7x

-26 - 15 = -41

The final answer to this one is 14x² + 7x - 41

You might be interested in

A) Write 84 as the product of prime factors. Write the prime factors in ascending order.

timofeeve [1]

84 = 2 x 2 x 3 x 7 which can also be written 2² x 3 x 7.

Ascending order means to keep the factors in order from least to greatest.

3 0

2 years ago

X+y=5 x^y+y^x=17 solve for the value of y and x

pentagon [3]

X = 2
y = 3 

2 + 3 = 5 
2³ + 3² = 17 

------------------- 

BUT: 

x + y = 5 
x^y + y^ x = 17 

y = 5 - x

7 0

3 years ago

HELP PICTURE SHOWN!!!!

laila [671]

I hate APEX!

A is right since the graph would start at 2 and go towards negative infinity

D is right both graphs approach +2 as thier highest values

6 0

2 years ago

Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a rhombus.

4 0

1 year ago

Read 2 more answers

1. Perimeter of a hexagon with 3.25-m sides.

Alex777 [14]

2) $3.85
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5 0

3 years ago