3 years ago

I'm in algebra 1 please help i'm lost

Mathematics

1 answer:

german3 years ago

5 0

The answer is #3... 2 and -6! Hope this helped!

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For the function f(x)=|x−7|−4, evaluate f(x+1).

GarryVolchara [31]

Answer:

$\displaystyle{f(x+1)=|x-6|-4}$

Step-by-step explanation:

To evaluate $\displaystyle{f(x+1)}$ , substitute $\displaystyle{x}$ to $\displaystyle{x+1}$ so we should have:

$\displaystyle{f(x+1) = |x+1-7|-4}$

Evaluate the expression and finally, we have:

$\displaystyle{f(x+1)=|x-6|-4}$

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2 years ago

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polet [3.4K]

Answer:

is there any pic to refer the question?

Step-by-step explanation:

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2 years ago

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kicyunya [14]

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One of the Numbers is -151 and the other is -144

Step-by-step explanation:

Set up the equations then solve

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3 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$

Therefore, the values of $b$ are:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

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3 years ago

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6th grade math I mark as brainliest

anygoal [31]

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you should put true

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3 years ago

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