All categories

3 years ago

Factorise 6x²+x-12 PLEASE HELP!

Mathematics

2 answers:

hichkok12 [17]3 years ago

7 0

6x^2 + x - 12
= (3x - 4) (2x + 3)

Hope this helped and Happy New Year! :)

irga5000 [103]3 years ago

4 0

(3x-4) (2x+3)
hope you good the answer right
good luck

You might be interested in

A box of blueberries is 2/5 full. Janet and her friends had each eaten 1/10 of a box of blueberries. How many people are blueber

anyanavicka [17]

In this problem, we have to find the factor which will make (1 / 10) equal to (2 / 5). Therefore we can write it as:

x (1 / 10) = 2 / 5

where x is the number of people who ate the blueberries

x = (2 / 5) / (1 / 10)

x = 4

Therefore 4 people ate the blueberries.

7 0

3 years ago

Read 2 more answers

Vickie made a recipe for 144 fluid ounces of scented candle wax. How many 1 cup candle molds can she fill with the recipe???

vlabodo [156]

1 cup = 8 fluid
So 144 fluid = 144/8 = 16 cups
So 16 cups candle moles she can fill with the recipe.

8 0

3 years ago

How many three-digit even numbers can be formed using digits from the set {1, 2, 3, 4, 5, 6, 7}

castortr0y [4]

The unit numbers can be 2,4,6.Suppose 2 as the unit number we can form 20 numbers the same way for 4 and 6 so totally 60 numbers.

6 0

3 years ago

)) Two tailors, Kristen and Layla, sit down to do some embroidery. Kristen can embroider 5

serious [3.7K]

Answer:

2 hours or less depending on how skilled or how they're felling that day

Step-by-step explanation:

4 0

3 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers