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Dima020 [189]
4 years ago
8

Sean has worked 66 hours over the last 10 days without a day off. He worked either a 6 hour day or an 8 hour day. During the 10

day period, how many days did Sean work an 8 hour day?
Mathematics
1 answer:
marysya [2.9K]4 years ago
7 0
He worked an 8 hour day 3 days.

Let x be the number of 8 hour days he works.  Then 10-x is the number of 6 hour days he works.

8x + 6(10-x) = 66

Using the distributive property,
8x + 6*10 - 6*x = 66
8x + 60 - 6x = 66

Combining like terms,
2x + 60 = 66

Subtract 60 from both sides:
2x + 60 - 60 = 66 - 60
2x = 6

Divide both sides by 2:
2x/2 = 6/2
x = 3

There were 3 days he worked 8 hours.
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VMariaS [17]

gcd  =  6  ⋅  d

Step-by-step explanation:

We have that  

6 d ^2  =  6  ⋅  d  ⋅  d and  18 d  =  3  ⋅  6  ⋅  d  hence the  gcd  =  6  ⋅  d

(Hope this helps <3)

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Solve for v =<br> Ok thankyou sm
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What’s -10/-1 simplified<br> What’s -1/-3 simplified
Jlenok [28]

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10 and 1/3

Step-by-step explanation:

4 0
3 years ago
The acceleration of a Maserati (sports car) is proportional to the difference between 250 km/h and its velocity. If the car can
Igoryamba

Answer:

a) The differential equation for the velocity is given by

(dv/dt) = k(250 - v)

b) v(t) = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾

With units of km/h

Step-by-step explanation:

Acceleration, a ∝ (250 - v)

But acceleration is widely given as dv/dt

(dv/dt) ∝ (250 - v)

(dv/dt) = k(250 - v)

where k = constant of proportionality

(dv/dt) = k(250 - v)

b) (dv/dt) = k(250 - v)

dv/(250 - v) = k dt

∫ dv/(250 - v) = ∫ k dt

- In (250 - v) = kt + c (where c is the constant of integration)

v(0) = 0; meaning, at t = 0, v = 0

- In 250 = 0 + C

c = - In 250 = - 5.52

- In (250 - v) = kt - 5.52

In (250 - v) = 5.52 - kt

250 - v = e⁽⁵•⁵² ⁻ ᵏᵗ⁾

v = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾

With units of km/h

i hope this work for you

and sory if im wrang

4 0
2 years ago
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