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2 years ago

Solve the quadratic in form equation x^4-14x^2+45=0

Mathematics

1 answer:

Anastaziya [24]2 years ago

7 1

X⁴-14x²+45=0
(x²) ²-14x²+45=0
let y=x²
y²-14y+45=0
(y-9) (y-5) =0
y=9 or y=5
x²=9 or x²=5
x=±3 or x=±√5

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hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w

GuDViN [60]

Answer:

$\frac{-5 \pm \sqrt{13} }{6}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

$\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}$

Step 2: Evaluate

Evaluate Exponents: $\frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}$
Evaluate Multiplication: $\frac{-5 \pm \sqrt{25-12} }{6}$
Evaluate Subtraction: $\frac{-5 \pm \sqrt{13} }{6}$

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2 years ago

Write 9.3 million in scientific notation

svetoff [14.1K]

9.3 × 107 would be the scientific notation

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2 years ago

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What is 7% tax on a $9.79 purchase

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2 years ago

Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.

chubhunter [2.5K]

The value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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1 year ago

What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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2 years ago