Given that f(x)=x^2-1 and g(x)=x-4, the value of (f*g)(10) will be:
f*g=(x^2-1)(x-4)
=x^2(x-1)-1(x-4)
=x^3-x^2-x+4
=x^3-x^2-x+4
next we find (f*g)(10), we substitute the value of x in our expression.
(f*g)(10)=10^3-10^2-10+4
=894
The interval for the function to be negative will be (-∞<x<-7).
<h3>What is a function?</h3>
A function in mathematics set up a relatioship between the dependent variable and independent variable. on changing the value of the independent variable the value of the dependent variable also changes.
Here we have a function:-
g(x) = ∛(x+6)
If we put the value of x lesser than 6 in the function we will always get a negative value so the interval will be:-
(-∞<x<-7).
Therefore interval for the function to be negative will be (-∞<x<-7).
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Answer:
3 < x < 27
Step-by-step explanation:
15 - 12 < x < 15 + 12
3 < x < 27
9/10n + 6 = 51
9/10n = 51 - 6
9/10n = 45
n = 45 * 10/9
n = 450/9
n = 50
I suppose they could be if there was a lot of traffic going in a certain direction to allow it to clear