PLEASE HELP WITH THESE QUESTIONS

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

I'll work on the first one soon....

kifflom [539]3 years ago

5 0

For the second question answer -10 and -4
The second one factor two numbers that add to 14 and when you multiply the numbers you get 40. Are 10 and 4
(X+10)(X+4)
X+10=0
Subtract 10 on both sides
X=-10. Answer
X+4=0 subtract 4
X=-4
3rd question X= 2 and X= -9

Two numbers that add to -7 and multiply to -18 are -2+9=-7. -2 times 9=-18
(X-2)(X+9)=0
X-2=0 X= 2. X+9=0 X=-9

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3 years ago

Find the unknown side length. Write your answer in simplest radical form.

Eva8 [605]

Answer: 1. x= 20 units, 2. x= $5\sqrt{3}$ units 3. x= $4\sqrt{2}$ units.

Step-by-step explanation:

In a right triangle,

$Hypotenuse^2= Perpendicular^2+Base^2$ (Pythagoras theorem)

1. Hypotenuse = x , Base = 16, Perpendicular = 12

$\Rightarrow\ x^2 =12^2+16^2\\\\ \Rightarrow\ x^2=144+256\\\\ \Rightarrow\ x^2=400\\\\ \Rightarrow\ x=\sqrt{400}=20$

2. Hypotenuse = 14 , Base = 11, Perpendicular = x

$\Rightarrow\ 14^2=x^2+11^2\\\\\Rightarrow\ 196=x^2+121\\\\\Rightarrow\ x^2=196-121\\\\\Rightarrow\ x^2 = 75\\\\\Rightarrow\ x=\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}$

3. Hypotenuse = 9 , Base = x, Perpendicular =7

$\Rightarrow\ 9^2=x^2+7^2\\\\\Rightarrow\ 81= x^2+49\\\\\Rightarrow\ x^2=81-49\\\\\Rightarrow\ x^2=32\\\\\Rightarrow\ x=\sqrt{32}=\sqrt{16\times2}\\\\\Rightarrow\ x=4\sqrt{2}$