Answer:
Option D is correct.
Length of PQ is 36 unit.
Explanation:
If the measures of two sides in one triangle are proportional to the corresponding sides in the another triangle and their including angles are congruent, then the triangles are similar.
Given: Right angle triangle ABC at B , Length of AB = 12 unit and length of BC = 11.5 unit and in right angle triangle PQR at Q , length of QR = 34.5 unit.
Also it is given that Angle A is congruent to angle P and angle C is congruent to angle R.
To find the length of QR:
It is given that ΔABC and ΔPQR are Similar triangle
then, by the definition of similar triangle:

Substitute the value of AB, QR and BC to solve for PQ;
or

On simplify:

Therefore, the length of side PQ is 36 units.
The chance is 3/5 that the light will be green.
Added together the total seconds for the traffic light to complete the cycle is 120 (38+72 (1 min and 12 sec) +10.
And the green light proportion is: 72/120
We simplify by dividing by 12, which is a factor and we get: 6/10 that simplifies to 3/5.
Hope this helps!
Let's first find the slope. This is (y_2 - y_1)/(x_2 - x_1), where (x_1, y_1) and (x_2, y_2) are points.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is

.
Answer:
There were 10 flies originally
Step-by-step explanation:
Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;
V = I(1+r)^d
where V is the number of flies on a particular day
I is the initial number of flies
r is the constant increase in percentage
and d is the number of days.
So we have for the second day;
60 = I(1+r)^2 ••••••(i)
For the fourth day, we have;
360 = I(1+r)^4 ••••••••(ii)
divide equation ii by i; we have;
360/60 = (1+r)^4/(1+r)^2
6 = (1+r)^2
(√6)^2 = (1+r)^2
1 + r = √6
r = √6 - 1
So we can substitute the value of r in any of the equations to get I which is the initial number of flies
Let’s use equation 1
60 = I(1 + r)^2
60 = I(1 + √6 -1)^2
60 = I(√6)^2
60 = 6I
I = 60/6
I = 10 flies