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Olin [163]
3 years ago
10

A factory machine produces 5/10 kilograms of chocolate every 1/6 minutes.

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

Answer:

3 kg chocolates per minute.

Step-by-step explanation:

It is given that factory machine produces 5/10 kilograms of chocolate every 1/6 minutes.

Chocolate = 5/10 kg

Time = 1/6 minute

We need to find the rate.

Rate=\dfrac{\frac{5}{10}}{\frac{1}{6}}

It can be rewritten as

Rate=\dfrac{5}{10}\times \dfrac{6}{1}

Rate=3

Therefore, the machine produce 3kg chocolate per minute.

Greeley [361]3 years ago
3 0
0.5 1 per 6
hope that helps:)

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Answer:

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Step-by-step explanation:

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The anwser is 70.69

If the cook makes twice as much beef then the number of hamburgers would be two times larger which would be 141.39.

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Zigmanuir [339]

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Percy solved the equation x2 + 7x + 12 = 12. His work is shown below. Is Percy correct? Explain.
antoniya [11.8K]
= > x² + 7x + 12 = 12

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Percy did correct till this step. But by doing like this, Percy can't get the values of the variable x.



Percy should follow the following steps :

= > x² + 7x + 12 = 12


Add -12 on both sides,


= > x² + 7x + 12 - 12 = 12 - 12

= > x² + 7x = 0

= > x( x + 7 ) = 0

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= > ( x = 0 ) or ( x = - 7 )



Hence, required value(s) of x is 0 or -7
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