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Sloan [31]
3 years ago
12

Compare and contrast area and volume

Mathematics
2 answers:
Goryan [66]3 years ago
8 0
Volume is where you find the volume of an object using Length*width*height.
Area is when you find the area using length*height
Volume is when you calculate 3D shapes
Area is when you calculate 2D Shapes
levacccp [35]3 years ago
3 0
Both area and volume, in a vague way, can be seen as the measurement of the size of something.  They are different because area is the size of a two-dimensional shape (like a square or a triangle), and volume is the size of a three-dimensional shape (like a cube or a pyramid).
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liubo4ka [24]

Answer:

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2 years ago
What is the average rate of change for the function f(x)=3x^2 -5 on the interval −3 ≤ x ≤ −1 ?
Anestetic [448]

Answer:

-12

Step-by-step explanation:

Let b = -1 and a = -3

The average rate of change = \frac{f(b) - f(a)}{b - a}

f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2

f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22

f(b) - f(a) = -2 - 22 = -24

b - a = -1 + 3 = 2

\frac{f(b) - f(a)}{b - a} = -24/2 = -12

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3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
Simplify log(16x²) ± 2㏒(1÷×)
sp2606 [1]

Answer: just simplify condense it then your answer will be log(16)

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3 years ago
Given right triangle ABC with a=50, and m
kramer

Answer:

A=50 B=40 C=90

Step-by-step explanation:

B is a right angle so its automatically 90 degrees since A=50 and a triangle has to be 180 degrees 90+50= 140, 180-140=40.

3 0
2 years ago
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