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4 years ago

Examine the equation below.

2 answers:

4 0

Hey There!

Here is your answer:

The answer is "5 spaces away from each other".

Reason:

Because of these equations:

3+5=8
&
8-5=3

Is proves that that the distance away from each other is 5 spaces.

The answer is 5 spaces.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

ipn [44]4 years ago

3 0

You can use the (-5) part of the equation to say that 3 is 5 spaces left of 8

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Given that x=1.5 is the only solution to the equation 4x^2 - ax + b = 0, find the values of a and b. Show all workings.

evablogger [386]

If x = 1.5 is the only solution to the equation 4x² - ax + b =0 then

4x² - ax + b = 4(x - 1.5)² |use p² - 2pq + q² = (p - q)²

4x² - ax + b = 4(x² - 2x · 1.5 + 1.5²)

4x² - ax + b = 4(x² - 3x + 2.25)

4x² - ax + b = 4x² - 12x + 9 |subtract 4x² from both sides

-ax + b = -12x + 9

therefore

-a = -12 ⇒ a = 12 and b = 9

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3 years ago

What divided by what equals -2.2

Ugo [173]

Answer:

-4.2 divided by 2 equals -2.2

7 0

3 years ago

The half-life of a radioactive isotope is 10 years. About how long would it take 5 grams of the isotope to decay until there wer

valkas [14]

Answer:

Option A. 10 years

Step-by-step explanation:

we know that

Half-life $(t^{\frac{1}{2}})$ is the amount of time required for a quantity to fall to half its value as measured at the beginning of the time period.

In this problem $(t^{\frac{1}{2}})$ of a radioactive isotope is 10 years, which means that after 10 years half of the sample would have decayed and half would be left as it is.

After 10 years ( first half life) 5/2 = 2.5 g decays and 2.5 g remains left

8 0

3 years ago

Points S, L, and P on this grid represent the locations of the school, the library, and the park, respectively.

agasfer [191]

Using the distance formula, the distance from:

School to Library (SL) = 5 units.

Library to Park (LP) = 10 units.

<h3>What is the Distance Formula?</h3>

To calculate the distance between two points on a coordinate plane, the distance formula used is: $d = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}$ .

Given the coordinates of each location as:

School, S = (0, 4)
Library, L = (4, 1)
Park, P = (-4, -5)

Distance from School to Library (SL):

SL = √[(4−0)² + (1−4)²]

SL = √[(4)² + (−3)²]

SL = √25

SL = 5 units

Distance from Library to Park (LP):

LP = √[(4−(−4))² + (1−(−5))²]

LP = √[(8)² + (6)²]

LP = √100

LP = 10 units

Learn more about the distance formula on:

brainly.com/question/661229

#SPJ1

7 0

2 years ago

Please help? , no decimals please,please explain to see picture.

dalvyx [7]

Answer:

$8x\sqrt{3xy$

Step-by-step explanation:

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2 years ago