The degree of the polynomial is 5, therefore are 5 zeros (real or imaginary).
The given zeros are
1/3, 4 - 6i, and -2 + 11i.
Because complex zeros always occur as conjugate pairs, the remaining complex zeros are
4 + 6i and -2 - 11i.
Answer: 4 + 6i, -2 - 11i.
21x-9+63=180
21x+54=180
21x=126
x=6
Answer:
12.8
Step-by-step explanation:
Answer:6
Step-by-step explanation:
In a circle, a radius perpendicular to a chord bisects the chord. So BC = CA BC = 6 (given) x (or AC) = 6 Answer = 6. Tell me if I was right. Thanks.
