NOT NECESSARILY would a triangle be equilateral if one of its angles is 60 degrees. To be an equilateral triangle (a triangle in which all 3 sides have the same length), all 3 angles of the triangle would have to be 60°-angles; however, the triangle could be a 30°-60°-90° right triangle in which the side opposite the 30 degree angle is one-half as long as the hypotenuse, and the length of the side opposite the 60 degree angle is √3/2 as long as the hypotenuse. Another of possibly many examples would be a triangle with angles of 60°, 40°, and 80° which has opposite sides of lengths 2, 1.4845 (rounded to 4 decimal places), and 2.2743 (rounded to 4 decimal places), respectively, the last two of which were determined by using the Law of Sines: "In any triangle ABC, having sides of length a, b, and c, the following relationships are true: a/sin A = b/sin B = c/sin C."¹
Answer:
x = 11/10
Step-by-step explanation:
we have from statement:
-1=1 - 4(-5+4x) – 4x
we apply distributive property:
-1 = 1 -4*(-5) -4*(4x) -4x
so we have:
-1= 1+20 -16x -4x
-1 = 21 -20x
-22=-20x
so we have:
x=22/20
x=11/10
we can substitute the x value found:
-1 = 1 - 4(-5+4*(11/10)) – 4*(11/10)
-1 = 1+20 -17.6 -4.4
-1 =21 -22
so we have:
-1 = -1
The ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.
<h3>Ratio</h3>
A ratio is a number representing a comparison between two named things. It is also the relative magnitudes of two quantities usually expressed as a quotient.
Mr Rowley:
- Homework papers = 16
- Tickets to return = 2
Ratio of number of homework papers to number of exit tickets = 16 : 2
= 16 / 2
= 8 / 1
= 8 : 1
Ms Alvera:
- Homework papers = 64
- Tickets to return = 60
Ratio of number of homework papers to number of exit tickets = 64 : 60
= 64/60
= 16 / 15
= 16 : 15
Therefore, the ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.
Learn more about ratio:
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2.43 x 10^2
Hope this helps
Answer: 4,863.1
Step-by-step explanation:
