A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
Answer:
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Step-by-step explanation:
cghgdfvv sscyhhffg asdfghjklppiutrwwazcb
Answer:
-2 - 5 = -7
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
1 + 1 + 1 + 1 = 2 + 2 = 4
Answer:
_____________________
a(6,-7) m(7,-5) letb(p,q)
Now,
Let a(6,-7) be x1 ,y1
Let b(p,q) be x2,y2
x,y = (7,-5)
Using Mid point Formula,
x = x1+x2 y= y1+y2
_____ , _____
2 2
7 = 6+p -5 = -7+q
___ , ____
2 2
or, 7×2=6+p , -5×2= -7+q
or, 14=6+p , -10= -7+q
or, p=14-6 , q= -7+10
p=8 , q= 3
Step-by-step explanation:
So , The coordinate of B(8,3)
Thank you
