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steposvetlana [31]
3 years ago
8

Help triangles please 8th grade

Mathematics
1 answer:
algol [13]3 years ago
3 0
The Side line is A, the top is B, and the diagonal line is C. Do A^2 x B^2 = C^2
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Solve for x. −12 = − 3/4 x A) 6 B) 8 C) 12 D) 16
shepuryov [24]

Answer:

D) 16

Step-by-step explanation:

5 0
3 years ago
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Solve the system. If there is more than one solution, write the general solution. x + y - 2z = 9 3x + y + 2z = 15 x - 5y + 22z =
Margaret [11]

Answer:

<h2>x = (12-k)/2, y = k, z = (k-6)/4 </h2>

Step-by-step explanation:

Given the system of equation

x + y - 2z = 9 ... 1

3x + y + 2z = 15 ...2

x - 5y + 22z = -27... 3

First let us reduce the system of equation into two with two unknowns.

Subtracting 1 from 3

y-(-5y) + (-2z-22z) = 9-(-27)

y+5y + (-24z) = 9+27

6y-24z = 36 ... 4

Multiplying equation 1 by 3 and subtracting from equation 2

3x + 3y - 6z = 27

3x + y + 2z = 15

On subtracting both;

(3y-y)+(-6z-2z) = 27-15

2y-8z = 12 ... 5

Equating 4 and 5

6y-24z = 36 ... 4

2y-8z = 12 ... 5

Multiplying equation 5 by 3 the equation becomes;

6y-24z = 36 ... 6

6y-24z = 36 ... 7

We can see that equation 6 and 7 are the same;

let y = k

6k - 24z = 36

k - 4z = 6

4z = k-6

z = k-6/4

Substituting y = k and z = k-6/4 into equation 1 to get x

From 1; x + y - 2z = 9 ... 1

x + k -2( k-6/4) = 9

x + k - (k-6)/2 = 9

x = 9+(k-6)/2-k

x = {18+(k-6)-2k}/2

x = (12-k)/2

The solutions to the system of equations are x = (12-k)/2, y = k, z = (k-6)/4 where k is any constant. This shows that the system of equation has infinite solutions.

7 0
3 years ago
Which of the following is an asset
Andrej [43]

Answer: B. House mortgage

Step-by-step explanation: Anything tangible or intangible that can be sold or profitable is considered an asset. Hope it helps! xo

7 0
3 years ago
How many solutions for linear equation 3x + 5y = 25 can be found so that −20 &lt; y &lt; 10, and x is an integer?
ch4aika [34]

Answer:

50

Step-by-step explanation:

3x = 25 - 5y

-100 < 5y < 50

-50 < -5y < 100

-25 < 25 - 5y < 125

-8.333 < x < 41.667

41+8+1 = 50

5 0
3 years ago
A cone and a pyramid are both 3 inches in height. If the radius of the base of the cone is 4 in and the a side of the square bas
kotegsom [21]
I got the answer of the cone
6 0
4 years ago
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