Answer: The required probability is 0.26.
Step-by-step explanation: Given that there are 60 red marbles and 40 blue marbles in a box 10 marbles are picked without replacement.
We are to find the probability of selecting 6 red marbles.
Since the marbles are picked up without replacement, so it is a situation of combination.
Let S denote the sample space of the experiment of drawing 10 marbles and E denote the event that 6 marbles are red.
So,

Therefore, the probability of event E is given by

Thus, the required probability is 0.26.
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
The percent of change is 9%
Answer:
500
Step-by-step explanation:
The problem statement tells you ...
300 = 0.60×voters
Dividing by the coefficient of the variable gives ...
300/0.60 = voters = 500
500 students voted in the election.
Cylinder Volume = PI * radius^2 * height
Cylinder Volume = 3.14 * 2^2 * 9
Cylinder Volume = 113.04 cubic inches
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