We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.
We are asked to find the percentage of students that are between 14 and 18 years old.
First of all, we will find z-score corresponding to 14 and 18 using z-score formula.
Similarly, we will find the z-score corresponding to 18.
Now we will find the probability of getting a z-score between 
and 
that is 
.
Using normal distribution table, we will get:
Let us convert 
into percentage.
Therefore, approximately 
of the students are between 14 and 18 years old.
A. If p = a number is negative and q = the additive inverse is positive, the original statement is p → q.
B. If p = a number is negative and q = the additive inverse is positive, the inverse of the original statement is ~p → ~q.
D. If q = a number is negative and p = the additive inverse is positive, the contrapositive of the original statement is ~p → ~q.
The time required to get a total amount of $5,900.00 with compounded interest on a principal of $5,000.00 at an interest rate of 5.75% per year 2.899 years
<h3>Compound Interest </h3>
Given Data
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 5.75/100
r = 0.0575 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(5,900.00/5,000.00) / ( 4 × [ln(1 + 0.0575/4)] )
t = ln(5,900.00/5,000.00) / ( 4 × [ln(1 + 0.014375)] )
t = 2.899 years
Learn more about compound interest here:
brainly.com/question/24924853
Answer:
These are the steps to do it since there is no equations provided
Step-by-step explanation:
1.) First, replace f(x) with y . ...
2.) Replace every x with a y and replace every y with an x .
3.)Solve the equation from Step 2 for y . ...
4.) Replace y with f−1(x) f − 1 ( x ) .
<em>Hope this helps :)</em>
