Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
.
To find:
The 
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]
Using the angle sum property in triangle AOB, we get
Hence, the measure of angle AOB is 120 degrees.
That's a pretty confusing one. I think it's 10 minutes.
Answer:
the value of x=33
the measure of each base angle = 42 ,69,69
Step-by-step explanation:
Bases od isosceles triangles are congruent,so
2(2x+3)=4x+6 (This is the sum ob both anlgles base)
All angles in a triangle add to 180
4x+6 + 42 = 180
4x = 132
x=33
2(33)+3= 69
69+69+42 = 180
Answer: The coordinates are (2.5, -1.5).
Explanation: The explanation is in the image.
Answer:
1/3 is the simplified form for given expression.
Step-by-step explanation:
Given that:
=![\sqrt[-3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B-3%5D%7B27%7D)
By simplifying:
Radical sign will be removed as follows:
= 
For removing the "-" sign from power, base will be inverted:
= 
27 can also be written as 3 * 3 * 3 = 3^3
So,
= 
= 
By simplifying we get:
= 1/3
i hope it will help you!
